A) 30 kJ
B) 20 kJ
C) 15 kJ
D) 10 kJ
E) 5kJ
Correct Answer: C
Solution :
\[R=\frac{230\times 230}{100}=529\,\Omega \] \[\therefore \] \[H=\frac{{{V}^{2}}}{R}\times t\] \[=\frac{115\times 115}{529}\times 10\times 60\] \[=15kJ\]You need to login to perform this action.
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