A) \[45{}^\circ \]
B) \[60{}^\circ \]
C) \[90{}^\circ \]
D) \[30{}^\circ \]
E) \[135{}^\circ \]
Correct Answer: C
Solution :
\[A(-1,3,2),B(2,3,5)\]and\[C(3,5,-2)\] \[\therefore \] \[AB=\sqrt{{{3}^{2}}+0+{{3}^{2}}}=\sqrt{18}\] \[CA=\sqrt{16+4+16}=6\] and \[BC=\sqrt{1+4+49}=\sqrt{54}\] \[\because \] \[A{{B}^{2}}+C{{A}^{2}}=B{{C}^{2}}\] \[\therefore \]\[\Delta ABC\] is right angled triangle, right angled at A. \[\therefore \] \[\angle A=90{}^\circ \]You need to login to perform this action.
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