A) 1/2
B) 1/3
C) 2/9
D) 9/2
E) 9
Correct Answer: D
Solution :
Required area \[=\int_{-1}^{2}{(2-{{x}^{2}}+x})dx\] \[={{\left( 2x-\frac{{{x}^{3}}}{3}+\frac{{{x}^{2}}}{2} \right)}^{2}}\] \[=4-\frac{8}{3}+2+2-\frac{1}{3}-\frac{1}{2}\] \[=\frac{9}{2}sq\text{ }unit\]You need to login to perform this action.
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