A) \[50{}^\circ C\]
B) \[100{}^\circ C\]
C) \[67{}^\circ C\]
D) \[33{}^\circ C\]
E) \[0{}^\circ C\]
Correct Answer: B
Solution :
Heat taken by ice to raise its temperature, to \[100{}^\circ C\] \[{{Q}_{1}}=1\times 80+1\times 1\times 100\] \[=180\text{ }cal\] Heat given by steam when condensed \[{{Q}_{2}}={{m}_{2}}{{L}_{2}}\] \[=1\times 540=540\text{ }cal\] As\[{{Q}_{2}}>{{Q}_{1}},\]hence, temperature of mixture will remain\[100{}^\circ C\].You need to login to perform this action.
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