A) 12.5
B) \[{{10}^{2}}\]
C) \[{{10}^{3}}\]
D) \[{{10}^{4}}\]
E) \[{{10}^{5}}\]
Correct Answer: E
Solution :
\[\frac{{{I}_{1}}}{{{I}_{2}}}={{(100)}^{({{m}_{1}}-{{m}_{2}})/5}}={{(100)}^{(14.5-2)/5}}\] \[={{(100)}^{5/2}}\] \[={{10}^{5}}\]You need to login to perform this action.
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