A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{6}\]
C) \[\frac{\pi }{3}\]
D) \[\frac{\pi }{5}\]
E) \[\frac{\pi }{4}\]
Correct Answer: B
Solution :
\[\int_{0}^{\pi /2}{\frac{\cos \theta }{\sqrt{4-{{\sin }^{2}}\theta }}}d\theta =\left[ {{\sin }^{-1}}\left( \frac{\sin \theta }{2} \right) \right]_{0}^{\pi /2}\] \[={{\sin }^{-1}}\left( \frac{1}{2} \right)=\frac{\pi }{6}\]
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