A) \[log\text{ }2\]
B) \[2log\text{ }2\]
C) \[{{(log\text{ }2)}^{2}}\]
D) \[\frac{1}{2}log\text{ }2\]
E) \[2\text{ }log\text{ }3\]
Correct Answer: A
Solution :
Let\[I=\int_{0}^{\pi /2}{\frac{\cos x}{1+\sin x}}dx\] \[=[\log (1+\sin x)]_{0}^{\pi /2}\] \[=\log 2-\log 1=\log 2\]
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