A) \[8:1\]
B) \[1:8\]
C) \[2:1\]
D) \[1:2\]
E) \[9:8\]
Correct Answer: A
Solution :
Given, \[{{Q}_{1}}=10units,{{Q}_{2}}=-20units\] After contact charges on both become same, i.e., \[Q=Q=\frac{10-20}{2}=-5\,units\] \[\therefore \] \[|{{F}_{1}}|=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{10\times 20}{{{r}^{2}}}\] and \[|{{F}_{2}}|=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{5\times 5}{{{r}^{2}}}\] Hence \[\frac{|{{F}_{1}}|}{|{{F}_{2}}|}=\frac{8}{1}\]
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