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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    \[\left| \begin{matrix}    x-2 & 2x-3 & 3x-4  \\    x-4 & 2x-9 & 3x-16  \\    x-8 & 2x-27 & 3x-64  \\ \end{matrix} \right|=0,\]then\[x\]is equal to:

    A)  \[-2\]                                   

    B)  3

    C)  \[-4\]                   

    D)         4

    E)  0

    Correct Answer: D

    Solution :

    \[\left| \begin{matrix}    x-2 & 2x-3 & 3x-4  \\    x-4 & 2x-9 & 3x-16  \\    x-8 & 2x-27 & 3x-64  \\ \end{matrix} \right|=0\] In the given options only\[x=4\]satisfy the given determinant.


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