A) any real number
B) for no real value of g
C) \[g=0\]
D) \[g<-2,g>2\]
E) \[g>0\]
Correct Answer: A
Solution :
The given circles cuts orthogonally, if \[2{{g}_{1}}{{g}_{2}}+2{{f}_{1}}{{f}_{2}}={{c}_{1}}+{{c}_{2}}\] \[2\times \frac{g}{2}\times 0+2\times 4\times 0=4-4\] This is true for any real value of\[g\].
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