CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    Equation of the circle passing through the intersection of ellipses \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\]and \[\frac{{{x}^{2}}}{{{b}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\]is:

    A)  \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]

    B)  \[{{x}^{2}}+{{y}^{2}}={{b}^{2}}\]

    C)  \[{{x}^{2}}+{{y}^{2}}=\frac{{{a}^{2}}{{b}^{2}}}{{{a}^{2}}+{{b}^{2}}}\]

    D)  \[{{x}^{2}}+{{y}^{2}}=1\]

    E)  \[{{x}^{2}}+{{y}^{2}}=\frac{2{{a}^{2}}{{b}^{2}}}{{{a}^{2}}+{{b}^{2}}}\]

    Correct Answer: E

    Solution :

    The equation of circle passing through the intersection of ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\]and \[\frac{{{x}^{2}}}{{{b}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\]                                 \[{{x}^{2}}+{{y}^{2}}=\frac{2{{a}^{2}}{{b}^{2}}}{{{a}^{2}}+{{b}^{2}}}\]


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