2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    In the electric circuit shown each cell has an emf of, 2V and internal resistance of\[1\,\Omega \]. The external resistance is\[2\,\Omega \]. The value of the current\[I\]is: (in amperes):

    A)  2            

    B)                         1.25

    C)  0.4                        

    D)         1.2

    E)  0.8

    Correct Answer: D

    Solution :

    \[Currents=\frac{net\,emf}{net\text{ }resistance}\] Or           \[I=\frac{2+2+2}{1+1+1+2}=\frac{6}{5}=1.2A\]


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