CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The equations of the tangents to the circle \[{{x}^{2}}+{{y}^{2}}-6x+4y-12=0\]which are parallel to the line\[4x+3y+5=0\]are:

    A) \[4x+3y+11=0\]and\[4x+3y+8=0\]

    B) \[4x+3y-9=0\]and\[4x+3y+7=0\]

    C) \[4x+3y+19=0\]and\[4x+3y-31=0\]

    D) \[4x+3y-10=0\]and\[4x+3y+12=0\]

    E) \[4x+3y+3=0\]and\[4x+3y-1=0\]

    Correct Answer: C

    Solution :

    The centre and radius of given circle are\[(3,-2)\]and 5 respectively. The equation of a line parallel to \[4x+3y+5=0\]is\[4x+3y+\lambda =0\] \[\therefore \]  \[\left| \frac{4\times 3+3\times (-2)+\lambda }{\sqrt{{{4}^{2}}+{{3}^{2}}}} \right|=5\] \[\Rightarrow \]               \[\lambda =19,-31\] \[\therefore \]Equation of tangents are \[4x+3y+19=0\]and\[4x+3y-31=0\]


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