A) \[2y+3=0\]
B) \[2x+1=0\]
C) \[2x-1=0\]
D) \[2y-1=0\]
E) \[2y-3=0\]
Correct Answer: E
Solution :
Equation of directrix of\[{{(x-1)}^{2}}=(2y-2)\]is \[y-2=-\frac{1}{2}\] \[\Rightarrow \] \[2y-3=0\]
You need to login to perform this action.
You will be redirected in
3 sec
