A) 16
B) 8
C) 4
D) 2
E) 1
Correct Answer: A
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\frac{\int_{4}^{f(x)}{2t\,\,dt}}{x-1}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{2f(x).f(x)}{1}\] \[=2f(1).f(1)=2.4.2=16\]You need to login to perform this action.
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