A) 5 and 34
B) 4 and 35
C) 4 and 34
D) 4 and 36
E) 6 and 36
Correct Answer: C
Solution :
The given AP is \[3,{{a}_{1}},{{a}_{2}},{{a}_{3}},{{a}_{4}},{{a}_{5}},{{a}_{6}},31\] \[\therefore \] \[31=3+7d\] \[\Rightarrow \] \[d=4\] \[\therefore \] \[{{a}_{1}}=3+4=7\] \[{{a}_{5}}=a+5d=3+20=23\] and \[{{a}_{6}}=a+6d=3+24=27\] \[\therefore \] \[{{a}_{6}}-{{a}_{5}}=27-23=4\] and \[{{a}_{1}}+{{a}_{6}}=7+27=34\]You need to login to perform this action.
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