A) \[2BL\sin \left( \frac{\theta }{2} \right){{(gL)}^{1/2}}\]
B) \[BL\sin \left( \frac{\theta }{2} \right)(gL)\]
C) \[BL\sin \left( \frac{\theta }{2} \right){{(gL)}^{3/2}}\]
D) \[BL\sin \left( \frac{\theta }{2} \right){{(gL)}^{2}}\]
E) \[BL\sin \left( \frac{\theta }{2} \right){{(gL)}^{5/2}}\]
Correct Answer: A
Solution :
\[h=L-L\cos \theta \] \[\Rightarrow \] \[h=L(1-\cos \theta )\] ...(1)You need to login to perform this action.
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