A) 60%
B) 40%
C) 50%
D) 45%
E) 55%
Correct Answer: A
Solution :
Let number of boys are\[x\]and number of girls are y. \[\therefore \] \[53(x+y)=55y+50x\] \[\Rightarrow \] \[53x+53y=55y+50x\] \[\Rightarrow \] \[3x=2y\] \[\Rightarrow \] \[x=\frac{2y}{3}\] \[\therefore \] Total number of students\[=x+y\] \[=\frac{5}{3}y\] \[\therefore \]Required percentage\[=\frac{3}{5}\times 100%\] = 60%You need to login to perform this action.
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