A) {2, 8}
B) \[\{-2,8\}\]
C) \[\{-2,-8\}\]
D) \[\{2,-8\}\]
E) \[\{\phi \}\]
Correct Answer: B
Solution :
Let \[y=f(x)={{x}^{2}}-6x-14\] \[\Rightarrow \] \[{{x}^{2}}-6x-14=2\] \[\Rightarrow \] \[{{x}^{2}}-6x-16=0\] \[\Rightarrow \] \[{{x}^{2}}-8x+2x-16=0\] \[\Rightarrow \] \[(x+2)(x-8)=0\] \[\Rightarrow \] \[x=\{-2,8\}\]You need to login to perform this action.
You will be redirected in
3 sec