A) \[\pm 3\]
B) \[\pm 2\]
C) 0
D) \[\pm 4\]
E) \[\pm 1\]
Correct Answer: D
Solution :
Let\[\alpha \]be the one root of equation\[{{x}^{2}}+bx+3=0,\]then another root will be\[3\alpha \]. \[\therefore \] \[4\alpha =-\text{ }b\] and \[3{{\alpha }^{2}}=3\] \[\Rightarrow \] \[a=\pm 1\] \[\therefore \] \[b=\pm 4\]You need to login to perform this action.
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