A) n
B) \[n+1\]
C) \[-n\]
D) \[-1\]
E) 1
Correct Answer: E
Solution :
\[{{(1+2x+3{{x}^{2}}+.....)}^{1/2}}\] \[={{[{{(1-x)}^{2}}]}^{1/2}}={{(1-x)}^{-1}}\] \[=1+x+{{x}^{2}}+....+{{x}^{n}}+...\] \[\therefore \]Coefficient of\[{{x}^{n}}=1\]You need to login to perform this action.
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