A) 5
B) 4
C) 3
D) 2
E) 1
Correct Answer: B
Solution :
Given, \[^{n}{{P}_{r}}\,=3024\] \[\therefore \] \[\frac{n!}{(n-r)!}=3024\] and \[^{n}{{C}_{r}}=\frac{n!}{r!(n-r)!}\] \[\Rightarrow \] \[126=\frac{3024}{r!}\] \[\Rightarrow \] \[r!=24=4!\] \[\Rightarrow \] \[r=4\]You need to login to perform this action.
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