CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The radius of the coil of a TG which has 10 turns is 0.1 m. The current required to produce a deflection of\[60{}^\circ ({{B}_{h}}=4\times {{10}^{-5}}T)\]is:

    A)  3 A                                        

    B)  1.1 A

    C)  2.1 A                    

    D)         1.5 A

    E)  2.6 A

    Correct Answer: B

    Solution :

    \[I={{B}_{H}}\times \frac{2R\tan \theta }{N{{\mu }_{0}}}\] \[=4\times {{10}^{-5}}\times \frac{2\times 0.1\times \tan 60{}^\circ }{10\times 4\pi \times {{10}^{-7}}}\]                 \[=1.1A\]


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