A) \[2F\]
B) \[\frac{F}{2}\]
C) \[\frac{F}{4}\]
D) \[F\]
E) \[4F\]
Correct Answer: D
Solution :
\[F=\frac{{{\mu }_{0}}}{4\pi }.\frac{6{{M}_{1}}{{M}_{2}}}{{{r}^{4}}}\] ...(1) When pole strength of each pole becomes double, then magnetic moment of each magnet becomes 4 times that of original magnet.
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