2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    A magnet of length 0.1 m and pole strength \[{{10}^{-4}}\]A-m is kept in a magnetic field of \[30\text{ }Wb/{{m}^{2}}\]at an angle\[30{}^\circ \]. The couple acting on it is\[......\times {{10}^{-4}}Nm\] .

    A)  7.5                        

    B)         3.0

    C)  4.5                        

    D)         6.0

    E)  1.5

    Correct Answer: E

    Solution :

    \[\tau =MB\sin \theta =m\times (2l)\times B\sin \theta \] \[={{10}^{-4}}\times 0.1\times 30\,\sin 30{}^\circ \] \[=1.5\times {{10}^{-4}}N-m\]


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