A) 0.5
B) 1.0
C) 1.5
D) 2.0
E) 5.5
Correct Answer: B
Solution :
\[q=\frac{N}{R}\phi =\frac{N}{R}(BA)\] \[\Rightarrow \]\[B=\frac{qR}{NA}=\frac{2\times {{10}^{-4}}\times 80}{40\times 4\times {{10}^{-4}}}=1\,Wb/{{m}^{2}}\]You need to login to perform this action.
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