A) 0.1 mm
B) 0.2 mm
C) 0.3 mm
D) 0.4 mm
E) 0.5 mm
Correct Answer: C
Solution :
\[e\sin \theta =\lambda \Rightarrow \sin \theta \approx \theta =\frac{\lambda }{e}\] \[\therefore \] \[x=f,\theta =f\lambda /e\] \[\therefore \]\[2x=\]separation between minima on either side of central maximum \[=\frac{2f\lambda }{e}\] Hence, \[e=\frac{2f\lambda }{2x}=\frac{2\times 1\times 600\times {{10}^{-9}}}{4\times {{10}^{-3}}}=0.3\,mm\]
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