A) \[1.24\times {{10}^{15}}Hz\]
B) \[2.4\times {{10}^{20}}Hz\]
C) \[1.24\times {{10}^{18}}Hz\]
D) \[2.4\times {{10}^{24}}Hz\]
E) \[2.4\times {{10}^{15}}Hz\text{ },\]
Correct Answer: B
Solution :
\[f=\frac{c}{\lambda }=\frac{c}{hc/E}=\frac{E}{h}\] \[\therefore \]\[f=\frac{1\times 1.6\times {{10}^{-13}}}{6.6\times {{10}^{-34}}}=2.4\times {{20}^{20}}Hz\]
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