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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    An electron enters uniform electric field maintained by parallel plates and of value \[EV{{m}^{-1}}\]with a velocity\[v\text{ }m{{s}^{-1}},\]the plates are separated by a distance d metre, then acceleration of the electron in the field is:

    A)  \[\frac{Ee}{m}\]                             

    B)         \[\frac{-Ee}{m}\]

    C)  \[\frac{Ed}{md}\]                           

    D)         \[Ee\frac{d}{m}\]

    E)  \[\frac{Em}{ed}\]

    Correct Answer: A

    Solution :

    \[F=eE\] Therefore, acceleration in electron due to force F \[a=\frac{F}{m}=\frac{eE}{m}\]


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