CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    The ionization potential of hydrogen is 13.6 V. The energy required to remove an electron from the second orbit of hydrogen is:

    A)  3.4 eV                 

    B)         6.8 eV

    C)  13.6 eV               

    D)         1.51 eV

    E)  \[-3.5eV\]

    Correct Answer: A

    Solution :

    Required energy\[=\frac{13.6}{{{2}^{2}}}=3.4\,eV\]


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