A) 0
B) \[-1\]
C) \[-2\]
D) \[\frac{1}{2}\]
E) \[-\frac{1}{2}\]
Correct Answer: A
Solution :
\[\because \]\[\cos x\log \left( \frac{1+x}{1-x} \right)\]is an odd function. \[\therefore \] \[\int_{-1/2}^{1/2}{\cos x\log \left( \frac{1+x}{1-x} \right)}dx=0\] \[\therefore \] \[k=0\]You need to login to perform this action.
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