CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically above a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is:

    A)  1200 m                                

    B)  0.33 km

    C)  333.3 km      

    D)         33 km

    E)  3.33km

    Correct Answer: E

    Solution :

    \[h=\frac{1}{2}g{{t}^{2}}\Rightarrow t=\sqrt{\frac{2\times 1960}{9.8}}=20s\] \[\therefore \]  \[s=AB=ut=600\times \frac{20}{60\times 60}\]                 \[=3.33\,km\]


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