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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2004

  • question_answer
    \[E_{Cu}^{o}=0.34\,V,\,E_{Zn}^{o}=0.76\,V\]. A Daniel cell contains\[0.1M\text{ }ZnS{{O}_{4}}\]solution and 0.01M \[CuS{{O}_{4}}\]solution at its electrodes. EMF of the cell is:

    A)  1.10V                                   

    B)  1.04V

    C)  1.16V                   

    D)         1.07V

    E)  1.00V

    Correct Answer: A

    Solution :

    \[C{{u}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Cu,\]              \[E{}^\circ =0.34\] \[Z{{n}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Zn\]                                \[E{}^\circ =0.76\] In the cell, \[Cu|\underset{anode}{\mathop{C{{u}^{2+}}}}\,||\underset{cathode}{\mathop{Z{{n}^{2+}}}}\,|zn\] In the cell,                 \[E_{cell}^{o}=E_{cathode}^{o}-E_{anode}^{o}\] \[=0.76-(-0.34)\] \[=1.10V\]


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