A) 6g
B) 5g
C) 4g
D) 2g
E) 1g
Correct Answer: D
Solution :
\[{{t}_{1/2}}=8\] days, \[N=125\text{ }mg,\text{ }{{N}_{0}}=?,T=32days\] \[T=n\times {{t}_{1/2}}\] \[32=n\times 8\] \[n=4\] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{4}}\] \[125={{N}_{0}}{{\left( \frac{1}{2} \right)}^{4}}\] \[125={{N}_{0}}\times \frac{1}{16}\] \[N=125\times 16=2000\text{ }mg=2g\]
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