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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    If the molecule of\[HCl\]were totally polar, the expected value of dipole moment is 6.12 D (debye), but the experimental value of dipole moment was 1.03 D. Calculate the percentage ionic character:

    A) 17                                          

    B) 83

    C) 50                          

    D)        zero

    E) 90

    Correct Answer: A

    Solution :

    Percentage ionic character \[=\frac{experimental\text{ }value\text{ }of\text{ }DM}{theoretical\text{ }value\text{ }of\text{ }DM}\times 100\] \[=\frac{1.03}{6.12}\times 100\] \[=17%\]


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