A) \[5,-35\]
B) \[-5,35\]
C) \[7,-32\]
D) \[-7,32\]
E) \[3,-13\]
Correct Answer: A
Solution :
The given equation of circle is \[{{x}^{2}}+{{y}^{2}}-2x+6y-6=0\] The centre and radius of circle are\[(1,-3)\]and 4 respectively. Length of perpendicular from\[(1,-3)\]to \[3x-4y+k=0\]is equal to radius 4. \[\therefore \] \[\left| \frac{3+12+k}{\sqrt{9+16}} \right|=4\] \[\Rightarrow \] \[15+k=\pm 20\] \[\Rightarrow \] \[k=20-15=5\] Or \[k=-20-15=-35\]You need to login to perform this action.
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