A) \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]
B) \[{{x}^{2}}-{{y}^{2}}={{a}^{2}}\]
C) \[x+y={{a}^{2}}\]
D) \[{{x}^{2}}-{{y}^{2}}=4{{a}^{2}}\]
E) \[{{x}^{2}}+{{y}^{2}}=4{{a}^{2}}\]
Correct Answer: B
Solution :
\[\because \]\[2\sqrt{{{g}^{2}}-c}=2a\] \[\Rightarrow \] \[{{g}^{2}}-x={{a}^{2}}\] ?. (i) and \[{{f}^{2}}=c\] ...(ii) On solving Eqs. (i) and (ii), we get \[{{g}^{2}}-{{f}^{2}}={{a}^{2}}\] \[\therefore \]Locus of centre of the circle is \[{{x}^{2}}-{{y}^{2}}={{a}^{2}}\]You need to login to perform this action.
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