CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    If the equation of base of an equilateral triangle is \[2x-y=1\]and the vertex is\[(-1,2),\]then the length of the side of the triangle is:

    A)  \[\frac{2}{\sqrt{15}}\]  

    B)         \[\sqrt{\frac{20}{3}}\]

    C)  \[\sqrt{\frac{8}{15}}\]  

    D)         \[\sqrt{\frac{15}{2}}\]

    E)  \[\sqrt{2}\]

    Correct Answer: B

    Solution :

    The length of perpendicular from\[(-1,2)\]to \[2x-y-1=0\]is \[\left| \frac{2(-1)-1(2)-1}{\sqrt{4+1}} \right|=\sqrt{5}\] \[\therefore \]Side of triangle \[=\frac{2}{\sqrt{3}}\times \sqrt{5}=\sqrt{\frac{20}{3}}\]


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