A) \[xyz=xz+y\]
B) \[xyz=xy+z\]
C) \[xyz=x+y+z\]
D) \[xyz=yz+x\]
E) \[xyz=x+yz\]
Correct Answer: B
Solution :
\[\because \]\[x=\sum\limits_{n=0}^{\infty }{{{\cos }^{2n}}\phi =1}+{{\cos }^{2}}\phi +{{\cos }^{4}}\phi +....\] \[=\frac{1}{1-{{\cos }^{2}}\phi }=\frac{1}{{{\sin }^{2}}\phi }\] Similarity\[=\frac{1}{1-{{\sin }^{2}}\phi }=\frac{1}{{{\cos }^{2}}\phi }\] and\[z=\frac{1}{1-{{\sin }^{2}}\phi {{\cos }^{2}}\phi }=\frac{1}{1-\frac{1}{x}.\frac{1}{y}}\] \[=\frac{xy}{xy-1}\] \[\Rightarrow \] \[xyz-z=xy\] \[\Rightarrow \] \[xyz=xy+z\]You need to login to perform this action.
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