A) 62 m
B) 301 m
C) 101 m
D) 75 m
E) 52 m
Correct Answer: E
Solution :
In\[\Delta ABC,\] \[\tan 60{}^\circ =\frac{h}{x}\] \[h=\sqrt{3}x\] ...(i) and in\[\Delta ABD,\] \[\tan 30{}^\circ =\frac{h}{x+60}\] \[\Rightarrow \] \[x+60=\sqrt{3}h\] ?. (ii) From Eqs. (i) and (ii) \[x+60=3x\] \[\Rightarrow \] \[x=30\text{ }m\] \[\therefore \] From Eq. (i) \[h=\sqrt{3}\times 30=1.732\times 30=51.96\text{ }m\] \[=52\text{ }m\] (approx.)You need to login to perform this action.
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