A) \[{{x}^{2}}+{{y}^{2}}+2x-2y=62\]
B) \[{{x}^{2}}+{{y}^{2}}+2x-2y=47\]
C) \[{{x}^{2}}+{{y}^{2}}-2x+2y=47\]
D) \[{{x}^{2}}+{{y}^{2}}-2x+2y=62\]
E) \[{{x}^{2}}+{{y}^{2}}-2x-2y=47\]
Correct Answer: C
Solution :
The equation of diameter are \[2x-3y=5\] ...(i) and \[3x-4y=7\] ...(ii) On solving Eqs. (i) and (ii), we get \[x=1,\]and\[y=-1\] \[\therefore \]Centre of circle\[=(1,-1)\] and radius of circle,\[r=7\] \[\therefore \]Equation of circle is \[{{(x-1)}^{2}}+{{(y+1)}^{2}}=49\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}-2x+2y=47\]
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