CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    A unit vector in the plane of\[\hat{i}+2\hat{j}+\hat{k}\]and\[\hat{i}+\hat{j}+2\hat{k}\]hand perpendicular to\[2\hat{i}+\hat{j}+\hat{k}\]is:

    A)  \[\hat{j}-\hat{k}\]

    B)                         \[\frac{\hat{i}+\hat{j}}{\sqrt{2}}\]

    C)  \[\frac{\hat{j}+\hat{k}}{\sqrt{2}}\]        

    D)         \[\frac{\hat{j}-\hat{k}}{\sqrt{2}}\]

    E)  \[5(\hat{j}-\hat{k})\]

    Correct Answer: D

    Solution :

    Let vector coplanar with\[\hat{i}+2\hat{j}+\hat{k}\]and \[\hat{i}+\hat{j}+2\hat{k}\]is \[x(\hat{i}+2\hat{j}+\hat{k})+y(\hat{i}+\hat{j}+2\hat{k})\] \[=(x+y)\hat{i}+(2x+y)\hat{j}+(x+2y)\hat{k}\] This vector is perpendicular to vector \[(2\hat{i}+\hat{j}+\hat{k})\]. \[\therefore \]\[[(x+y)\hat{i}+(2x+y)\hat{j}+(x+2y)\hat{k}]\]                                                 \[.(2\hat{i}+\hat{j}+\hat{k})=0\] \[\Rightarrow \]               \[2x+2y+2x+y+x+2y=0\] \[\Rightarrow \]                               \[5x+5y=0\] \[\Rightarrow \]                                               \[y=-x\] \[\therefore \]Equation of vector coplanar with given vectors is\[0\hat{i}+x\hat{j}-x\hat{k}\]. \[\therefore \]Required unit vector is \[\frac{x(\hat{j}-\hat{k})}{x\sqrt{1+1}}=\frac{\hat{j}-\hat{k}}{\sqrt{2}}\]


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