A) 33
B) 22
C) 21
D) \[-33\]
E) 54
Correct Answer: C
Solution :
\[\because \] \[p{{\lambda }^{4}}+q{{\lambda }^{3}}+r{{\lambda }^{2}}+s\lambda +t=\] \[\left| \begin{matrix} {{\lambda }^{2}}+3\lambda & \lambda -1 & \lambda +3 \\ \lambda +1 & 2-\lambda & \lambda -3 \\ \lambda -3 & \lambda +4 & 3\lambda \\ \end{matrix} \right|\] \[\Rightarrow \] \[p{{\lambda }^{4}}+q{{\lambda }^{3}}+r{{\lambda }^{2}}+s\lambda +t\] \[=({{\lambda }^{2}}+3\lambda )(5\lambda -4{{\lambda }^{2}}+12)\] \[-(\lambda -1)(2{{\lambda }^{2}}+9\lambda -9)+(\lambda +3)(2{{\lambda }^{2}}+10)\] On comparing both sides, we get \[t=-9+30=21\]You need to login to perform this action.
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