A) (4, 3, 5)
B) \[(4,9,-3)\]
C) (4, 9, 3)
D) \[(4,3,-3)\]
E) (4, 9, 5)
Correct Answer: B
Solution :
Let\[({{x}_{2}},{{y}_{2}},{{z}_{2}})\]be the co-ordinate of another end of diameter of sphere. Also centre of sphere is (3, 6, 1). \[\therefore \] \[\frac{2+{{x}_{2}}}{2}=3\] \[\Rightarrow \] \[{{x}_{2}}=4\] \[\frac{3+{{y}_{2}}}{2}=6\] \[\Rightarrow \] \[{{y}_{2}}=9\] and \[\frac{5+{{z}_{2}}}{2}=1\] \[\Rightarrow \] \[{{z}_{2}}=-3\] \[\therefore \]Required point is\[(4,9,-3)\].
You need to login to perform this action.
You will be redirected in
3 sec
