A) \[319{}^\circ C\]
B) \[592{}^\circ C\]
C) \[128{}^\circ C\]
D) \[60{}^\circ C\]
E) \[90{}^\circ C\]
Correct Answer: D
Solution :
If \[{{V}_{1}}=1{{V}_{2}}=1-\frac{15}{100},{{P}_{2}}=2{{P}_{1}},\] \[{{T}_{1}}=348,\,{{T}_{2}}=?\] \[=\frac{17}{20}\] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{{{P}_{1}}}{348}=2{{P}_{1}}\times \frac{17}{20\times {{T}_{2}}}\] \[\therefore \] \[{{T}_{2}}=60{}^\circ C\]You need to login to perform this action.
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