A) \[Li>Be>B>Na\]
B) \[Be>B>Li>Na\]
C) \[Na>Li>B>Be\]
D) \[Be>Li>B>Na\]
E) \[B>Be>Li>Na\]
Correct Answer: B
Solution :
Ionization energies increase in a period on Moving left to right while it decreases in a group on moving downward. The I.E. of Be is greater than B due to completely filled s-orbital. Hence, the order of IE is as: \[Be>B>Li>Na\]You need to login to perform this action.
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