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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2005

  • question_answer
    If for a plane, the intercepts on the co-ordinate axes are 8,4,4, then the length of the perpendicular from the origin on to the plane is:

    A)  \[\frac{8}{3}\]                  

    B)         \[\frac{3}{8}\]

    C)  \[3\]                    

    D)         \[\frac{4}{3}\]

    E)  \[\frac{4}{5}\]

    Correct Answer: A

    Solution :

    Equation of plane is\[\frac{x}{8}+\frac{y}{4}+\frac{z}{4}=1\] \[\Rightarrow \]               \[{{x}^{4}}-2y+2z=8\] Length of perpendicular from origin to \[x+2y+2z-8=0\]is                 \[\left| \frac{-8}{\sqrt{1+4+4}} \right|=\frac{8}{3}\]


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