A) 10
B) 50
C) 30
D) 40
E) 20
Correct Answer: E
Solution :
Let number of male workers\[=x\] and number of female workers\[=y\] \[\therefore \] \[206(x+y)=210x+190y\] \[\Rightarrow \]\[206x+206y=210x+190y\] \[\Rightarrow \] \[16y=4x\] \[\Rightarrow \] \[\frac{x}{y}=\frac{4}{1}\] \[\Rightarrow \] \[x=4y\] \[\therefore \]Total number of workers \[=5y\] \[\therefore \]% of female workers\[=\frac{y}{5y}\times 100%=20%\]You need to login to perform this action.
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