A) \[(2,0)\]
B) \[(\sqrt{2},\sqrt{2})\]
C) \[(\sqrt{2},-\sqrt{2})\]
D) \[(\sqrt{2},0)\]
E) \[(4,0)\]
Correct Answer: A
Solution :
\[{{z}_{2}}=z{{e}^{i\pi /4}}=(\sqrt{2}-i\sqrt{2})(\cos \pi /4+i\sin \pi /4)\] \[=\sqrt{2}(1-i)\frac{(1+i)}{\sqrt{2}}\] \[=1-{{i}^{2}}=1+1=2+0i\] \[\therefore \]Co-ordinate of new position are (2, 0).You need to login to perform this action.
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