A) \[-8\]
B) 8
C) \[-16\]
D) 9
E) none of these
Correct Answer: B
Solution :
Given relation is \[3\alpha +2\beta =16\] \[\Rightarrow \] \[2(\alpha +\beta )+\alpha =16\] \[\Rightarrow \] \[2\times 6+\alpha =16\] \[\Rightarrow \] \[\alpha =4\] \[\therefore \] \[{{\alpha }^{2}}-6\alpha +a=0\] \[\Rightarrow \] \[16-24+a=0\] \[\Rightarrow \] \[a=8\]
You need to login to perform this action.
You will be redirected in
3 sec
